Integral of (x^2)/sqrt(1 - 3x^2)
`int(dx)/(sqrt(1+2x-3x^(2)))`
Integral of x+1/squt of 3x^2+6x dx
Find Antiderivative of integral 2x sqrt(1-3x^2) dx using variable substitution
Integral Practice # 41: integral of (sqrt (3x^2 - 2x + 3))(3x - 1)dx from -1 to 1
( No Audio) Calculus-Integration: Integral of (x^2- 3x+1) / sqrt(1- x^2) by trigonometric substituti
Integrate √(1+3x-x^2)
関数 `sqrt(1+3x-x^2)` を積分します...
Evaluate the definite integral over [1, 9] for (3x -2)/sqrt(x) dx. Evaluation Theorem
Integral of (3x^2)*sqrt(1+x^3) (substitution)
平方根の積分(1-2x)
integral of 3x^2 / sqrt(1 - x^3) dx
(1/sqrt(x)-3x^2-1/x^4) dx の不定積分の求め方
Class 12th – Integral of 1/3x^2 + 13x – 10 | Integrals | Tutorials Point
Evaluate: (i) `int(2x+1)/(sqrt(3x+2))\\ dx` (ii) `int(3x+5)/(sqrt(7x+9))\\ dx`
`int sqrt((2x+1)/(3x+2))dx`
Integral of sqrt(1+x^2) (substitution + by parts)
INTIGRATION ( SQRT(1-3X-X^2)) dx =
integrate sqrt(3x - 2)dx
🔥 POV: Integration - Look at me! 👀 💪 | JEE 2024 | Math | Bhoomika Ma'am