Integral of 3x sqrt(25 - x^2) dx , x = 0 to 4
Evaluate the integral int_0^10 sqrt( 25 - (x-5)^2 ) using area formulas
`int_(-5)^(5)sqrt(25-x^(2))dx=`
微積分ヘルプ: ∫ 0 から (5/3) √(25-9x^2 ) dx まで - 三角関数の置換による積分
Integral of 1/√(x^2-25) || Integration by Trigonometric Substitution
Integrate | 1/(sqrt(25-x^2)) dx
Integral of 1/sqrt(25-x^2)
∫√(9-25x²)dx
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微積分ヘルプ: 積分 ∫ √(4x^2-25)/x dx - 三角関数の置換による積分
∫cos(20x)sin(25x)dx [-π/2, π/2]. MIT Integration Bee 2025, Qualifying Exam, Question 5. #integral
`int_(5/2)^5 (sqrt((25-x^2)^3))/(x^4) dx`
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