置換を用いた不定積分: Int(2x^4*sqrt(5+3x^5),x)

Calculus Help: Integral ∫ (x^2-3x+5) e^x dx - Integration by parts - 部品による統合

Integration (x+2)√3x+5 dx | Integrate x+2 times root under 3x+5 with respect to x

integral of 2x + 3 / x + 5 dx

Calculus Help: Integral ∫ 2x(x^2+3)^5 dx - Integration by substitution - 置換による統合

Evaluate the Integral x^3(2+ x^4)^5 dx with u substitution u = 2 + x^4

Integral of (x^2-3x-5)/(x-2)

Cracking Complex Integrals: How to Solve ∫(x+2) √((3x+5) ) dx Like a Pro | CUET 2024 | Class 12 |

Integral of (x^2-3x-5)/(x-2)

integrate (3x+5)/(x^3-x^2- x+1) dx || Integrate 3x+5/x^3-x^2-x+1

微積分ヘルプ: (x^3+5x^2-3x-5)/(x^2+x-3) dx の積分

x=0 から 1 までの (2x^4 - 3x^2 + 5) dx の定積分を求めます。

Integrate 2^x+3^x/5^x dx Exponential Function

Evaluate the Integral x(2x +5)^8 dx with the substitution rule

`int_(0)^(3)(2x^(2)+3x+5)dx`

integral of (2x + 3)e^(x^2 + 3x + 5)dx substitution

Integration Basic Formulas

`int(dx)/(2x^2+3x+5)=`

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