結果 : integral of x 2 from 0 to 1
3:32

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Fourier series of f(x) = (pi-x)/2 x= 0 to 2pi Deduce Π/4 = 1 - 1/3 + 1/5 - 1/7 + ...

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FOURIER SERIES: f(x)=1+(2x/pi) (x=-pi to 0) 1-(2x/pi) (x=0 to +pi) Deduce Π^2/8 = 1+1/3^2 + ...

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Double Integrals

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