Evaluate the Integral (x^2 + 1)(x^3 + 3x)^4 dx using the substitution rule
(x^2 - 2x + 4)/x^3 の積分
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Integral of (2x-3)/(2x^2-6x+5) (substitution)
`y=sqrt((x-2)(2x-3)(3x-4))` のとき、`(dy)/(dx)` を求めよ。
Integrate √2x^2+3x+4 dx
How to solve higher degree equations in casio fx-991ES PLUS
部分分数による積分
∫1/√(x² + x) dx = ? Solve without using substitution method.
「代入による積分」を使用した (2x+3)^4 の積分 - 完全ウォークスルー
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