Integrate (12x^3 + 3x^2 - 5) with the Power Rule
積分 (3x ^ 2 - 5) ^ 2 dx
Evaluate the Integral x^3(2+ x^4)^5 dx with u substitution u = 2 + x^4
5. Integrate ∫ √(3x² + 5) dx, int sqrt(3x²+5)dx Antiderivative calculus NEB12 Math Star Industries💥🌻
Integration By Substitution Problem#2. ∫ (x³+2x)⁵ (6x²+4) dx
Calculus Help: Integral ∫ (x^2-3x+5) e^x dx - Integration by parts - 部品による統合
Integral of (x^2-3x-5)/(x-2)
`int(dx)/(2x^2+3x+5)=`
(3x-2) / (x^2 - 2x) dx を x=4 から 5 まで積分します。(部分分数 #1!)
12. ∫ x³ dx/(2x⁴–3x²–5) Integrate x³dx/(2x⁴–3x²–5) Antiderivative Calculus🌻💥 Math Star Industries
How to integrate 3x/(6x^2+5) using a substitution
Q3 | Integrate 3x^2 dx | Integration of 3x^2 dx | Integral of 3x^2 dx | Integration 3 x square dx
Find: Integrate (2x-7)^8 dx; Integrate (3x+1)^5 dx
Q15 | Integrate 3x - 2 dx from 1 to 2 | Integral from 1 to 2 3x -2 dx | Definite Integral | Class 12
Q29 | Evaluate ∫(x^3+5x^2-4)/x^2 dx | Integral of (x^3+5x^2-4)/x^2 | Integration of (x^3+5x^2-4)/x^2
Integrate 3x+5/x^3-x^2-x+1 dx|JEE,11th,12th, CBSE, ICSE, State CETs
Evaluate: (i) `int(2x+1)/(sqrt(3x+2))\\ dx` (ii) `int(3x+5)/(sqrt(7x+9))\\ dx`
Evaluate the Integral (x+4)/(x^2 +2x +5) dx.
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(x^2-3x-5)/(x-2)、不定積分、微積分の積分方法