1/(1+x²)の積分 = Arctan(x) + c
An easy way to solve this brilliant integral - Integral (arctanx)^2 from 0 to 1
Integral of arctan(x)/(1+x^2) (substitution)
微積分ヘルプ: 積分 ∫ 0 から ∞ まで (x arctanx)/(1+x^2 )^2 dx - 部分積分
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