微積分ヘルプ: 積分 ∫ dx/(5-4x-x^2 )^2 - 三角関数の置換による積分
integrate sqrt(5 + 4x - x^2)dx
∫dx/5-2x^2+4x
10. ∫ (x–1)√(5–4x–x²) dx Integrate (x–1) sqrt(5–4x–x²) Antiderivative calculus Math Star Industries🌻
integral of dx/√5+4x-x^2 | how to integrate perfect square
22. Integrate x+3/root 5-4x-x^2
Integral dx / 5 - 2x² + 4x @EAG
Integrate the function ∫ root over x^2+4x-5 dx
integration (x) dx/(x^2+4x+5)^0.5 integration X into DX by root under X square + 4 x + 5
Integrate (x+3)/√5 -4x -x^2 dx | int[x+3]/sqrt[5-4x-x^2].dx Most Important concept of Integration
(x-2)/(x^2-4x+5) の積分 - 積分の例
integrate (x+3)/sqrt(5-4x+x^2) dx || `int[x+3]/sqrt[5-4x-x^2].dx`
次の積分 `int sqrt(5-4x-x^(2)) dx` の値を求めます。
評価: `int 1/sqrt(5-4x-2x^2)dx`
Integrate the functions ∫ 1/root over 5 - 4x - 2x^2 dx
Evaluate `int((x+3))/(sqrt(5-4x-x^(2)))dx`.
`int[x+3]/sqrt[5-4x-x^2].dx`
integral of dx/x2+4x+8 || integral of dx/x²+4x+8 || Integration of dx/x^2 +4x +8 || #term2