結果 : integrate log cos x dx from 0 to pi 2
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integration 0 to 'pi/2' ln(cosx)dx || integration 0 to 'pi/2' log(sinx)dx || 0 to pi/2 ln(cosx)dx

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integrate log(cos x) dx from 0 to pi / 2 = integrate log(sin x) dx from 0 to pi / 2 = - pi/2

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Prove that: `int_(0)^(pi//2) log (sin x) dx =int_(0)^(pi//2) log (cos x) dx =(-pi)/(2) log 2`

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If `int_(0)^(pi//2) log cos x dx =(pi)/(2)log ((1)/(2)),` then `int_(0)^(pi//2) log sec x dx =`

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#04 Definite Integral | निश्चित समाकलन | Integration of log sin x | Integration of log cos x

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