How do I integrate log (cos x) from 0 to pi/2? Log sinx dx from 0 to pi by 2
Integration 0 se π/2 Integration log cos x dx Most important question
integration 0 to 'pi/2' ln(cosx)dx || integration 0 to 'pi/2' log(sinx)dx || 0 to pi/2 ln(cosx)dx
`int_0 ^ (pi/2) log(cosx) dx=`
integrate log(cos x) dx from 0 to pi / 2 = integrate log(sin x) dx from 0 to pi / 2 = - pi/2
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Prove that: `int_(0)^(pi//2) log (sin x) dx =int_(0)^(pi//2) log (cos x) dx =(-pi)/(2) log 2`
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