#integrals ||Evaluate integral 0 to pi by2 \sin{x}\cos{x}} by \cos^{2}{x}+3\cos{x}+2} dx

積分 - sin x cos x/cos^2 x + 3 cos x + 2 dx を 0 から Pi/2 まで積分します。

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The value `int_0^(pi/2)(sinxcosx)/(cos^2x+3cosx+2)dx` is

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∫2+3cosx/sin^2 x dx, ∫(2Tanx - 3Cotx)^2 dx|Integrations|Integrals|Lec211

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