Integrate (x+3)/√5 -4x -x^2 dx | int[x+3]/sqrt[5-4x-x^2].dx Most Important concept of Integration

Calculus Help: Integral of ∫ (x+3)/√(5-4x-x^2 ) dx - Integration by trigonometric substitution

`int[x+3]/sqrt[5-4x-x^2].dx`

Evaluate `int((x+3))/(sqrt(5-4x-x^(2)))dx`.

integrate (x+3)/sqrt(5-4x+x^2) dx || `int[x+3]/sqrt[5-4x-x^2].dx`

`int(x+3)/(sqrt(5-4x-x^2))dx`

Integrate the function ∫ x+3/root over 5-4x-x^2 dx

Calculus Help: Integral of (2x+3)/√(5+4x-x^2 ) dx - Integration by substitution

【定積分】このカタチはアノ置換です

`(x+3)/(sqrt(5-4x-x^2))`

22. Integrate x+3/root 5-4x-x^2

代入を使用して積分 [(x+3)/sqrt(5-4x-x^2)] を評価します。

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integrate sqrt(5 + 4x - x^2)dx

(i) `(x+3)/sqrt(5-4x-x^(2)) dx` का मान ज्ञात कीजिए।

Integrate(sqrt (5-4x-x^2 ))

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