Integral of x^3/(1+x^4) (substitution)
Evaluate the Integral (x^2 + 1)(x^3 + 3x)^4 dx using the substitution rule
Integral of x(x+1)^3
Integration of Mod ( X - 1) + Mod (X - 2) + Mod ( X - 3) from 1 to 4 @StudyPointPro
integral ' -1 to 2 mod(x^3-x)dx' || integrate '|x ^ 3 - x|' dx from - 1 to 2 ||
integrate (x+x^3)^1/3/x^4 | integral (x plus x cube) ka whole power 1/3 upon x power 4 |
Integral Practice #4: integral of (x^3)(sqrt(x^2 + 1)) (MIT integration bee 2016 qualifying round)
Integrate ∫((x-3) e^x)/(x-1)^3 dx | Integration of x - 3 by x - 1 whole cube into ex dx
DEFINITE INTEGRAL
find the integral of (4x^3 + 3)/(x^4 + 3x) dx
Integral of x^3 / ( x^2 + 1)^3 dx
Integration By Partial Fractions
Q18 | Integration of limit 1 to 4 of |x-1| + |x-2 | + |x-3| dx
integrate 1 to 4 "( |x-1|+ |x-2|+|x-3| )"dx
Q5 | Integrate root x dx from 1 to 4
Integration 0 to 1 ( x^4) * ( log 1/x )^3
integral of x^2(2x^3 - 1)^4 dx
The value of the integral `int_(1//3)^(1)((x-x^(3))^(1//3))/(x^(4))dx` is
@btechmathshub7050積分の順序の変更 - 二重積分
Calculus: Indefiinte Integration - Integral of 1/ (4 Cosx + 3 Sinx )