Integral of x sqrt(2x + 1) ❖ Calculus 1 ❖ Square Root Integrals

integrate (x + 1) * sqrt(2x - 1) dx

x sqrt(2x+1) の積分 (解)

Integral of x/(2x - 1)

x^2/(x^2+1)の積分

Integration of 1/x sqrt(2x) (Solution)

integrate sqrt(x) (2x - 1) dx

integrate x.sqrt(1+2x^2) dx || Integrate x sqrt(1 + 2x^2)

integrate x/(sqrt(1 - 2x)) dx

Integral of (x+1)/sqrt(x^2+2x+5) (substitution)

Evaluate the Integral (2x +1)/(x^2 +x +1) dx. Integrate

Q304 | ∫ x√(1+2x^2) dx | Integral of x sqrt(1+2x^2) | Integration of x square root 1 + 2 x square

`int(x+1)sqrt(2x-1)dx=`

derivative x/sqrt(2x-1) by using the substitution method

`int(2x-1)/(sqrt(x^(2)-x-1))dx`

アークサイン関数を用いたsec^2(x)/sqrt(1 - tan^2(x))の積分

「評価: `int(2x+1)/sqrt(x^2+2x-1)dx`」

Integral with substitution and square root. 1/sqrt(2x-1)

Evaluate: `int(x+1)/(sqrt(2x-1))\\ dx`

If `int (x+1)/(sqrt(2x-1))dx = f(x)sqrt(2x-1)+C`, where C is a constant of integration, then f(x)