1/(x^2+a^2) の積分
how Richard Feynman would integrate 1/(1+x^2)^2
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1/x^2 の不定積分
微積分 || 積分 || (x⁴+3x²-1) と (x+2/x²) の極限での積分。
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1/(x^2-a^2)の積分
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