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The value of integral ∫_0^2〖(8-x^3 )^(-1/3) dx〗 in terms of Beta function is:(a) 1/3 B(1/3,2/3)

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∫(1/3 √(x)) d x Will be (1) x^3/4/2+C (2) x^2/3/3+C (3) x^2/3+C (4) x^2/3/2+C riysicsalldh 2/2/4

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integral ' -1 to 2 mod(x^3-x)dx' , integrate '|x ^ 3 - x|' dx from - 1 to 2 |x3 - x| dx #cbse

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