微積分ヘルプ: 積分 ∫ (x+1)/(9x^2+6x+5) dx - 三角関数の置換による積分
Integrate 1/(9x^2 + 6x +5) // Integration by substitution // समाकलन // प्रतिस्थापन विधि
class 12 math exercise 7.4 Question 11 integral 1/(9x^2+6x+5) dx | ∫1/(9x^2+6x+5) dx
Integrate the function ∫ 1/9x^2+6x+5 dx
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Integral 1/(9x^2+6x+5) || integral Integral 1/(9x^2+6x+5)
Integrate the function 1/9x²+6x+5 .
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関数 `1/(9x^2+6x+5)` を積分します...
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