Evaluate `int_(1/2)^(2)1/xsin(x-1/x).dx`

S_n = int_0^(pi//2) (sin (2n - 1)x)/(sin x) dx の場合、V_n = int_0^(pi//2) ((sin nx)/(sin x))^2 dx a...

`int x^(2) sin x dx` is equal to

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Evaluate `int(cos x)/((1-sinx)(2-sinx))dx.`

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`int_(0)^(pi//2) ""(sin x - cos x)/( 1-sin x * cos x) dx ` is equal to

Integration of log sin x dx from 0 to π/2 @StudyPointPro

`int_(0)^(pi//2)(sin x) / (1+ cos^(2) x ) dx = `