Q10 | Integral Of ((3sinx-2)cosx)/(5-cos^2 x - 4sinx) | Int((3sinx-2)cosx)/(5-cos^2 x-4sinx)

微積分ヘルプ: 積分 ∫ (3sinx-2)cosx/(5-cos^2⁡x-4sinx) dx - 置換積分 - 三角関数

評価: `int((3sinx-2)cosx)/(5-cos^2x-4sinx)dx`

Integrate the function ∫ (3sinx-2)cosx/5-cos^2x-4sinx dx

微積分ヘルプ: (3sinx-2)cosxdx/(5-cos^2⁡x-4sinx) の積分 - 置換積分

`int (3sinx-2)cosxdx/(5-cos^2x-4sinx)`

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`int((3sinx - 2)cosx)/((5-cos^(2) x - 4sinx))` का मान ज्ञात कीजिए।

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微積分ヘルプ: ∫ (2cosx-3sinx)/(6cosx+4sinx) dx - 置換積分

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