How to find the indefinite integral of [(x-2)/(x^2-4x+1)^2]dx
微積分ヘルプ: (8x^2-4x+7)/((x^2+1)(4x+1)) dx の積分 - 割り算による積分
Integration by Partial Fractions: Integral of (8x^2 - 4x + 7)/((x^2 + 1)(4x + 1)) dx