評価: int(3x+5)/sqrt(x^2-8x+7)\\ dx | クラス 12 | 黒板解答 | 数学 | Doubtnut

Integration (Calculus)

微積分ヘルプ: 積分 ∫ 3x^2 (x^3+5)^7 dx - 置換積分 - テクニック

Integration of Rational Functions By Completing The Square - Calculus

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Evaluate \[ \int \frac{3 x+5}{\sqrt{x^{2}-8 x+7}} d x \]

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置換を用いた不定積分: Int(2x^4*sqrt(5+3x^5),x)

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`int(6x-8)/(3x^2-8x+5)dx`

`int(5x-2)/sqrt(3x+7)dx`