Find the integral (4x-3)/(2x^2 - 3x +1) dx without using techniques of partial fractions

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Evaluate Integral 4x+3/ 2x+1dx

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`int(x^3+4x^2-3x-2)/(x+2)& dd; x`

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微積分ヘルプ: (2x^3-3x^2+4x-2)/(2x^2-3x+1) dx の積分 - 部分分数による積分

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微積分ヘルプ: (4x-1)/(2x^2-3x+1) dx の積分 - 部分分数による積分

How to find the indefinite integral of (4x^3-2x^2+1)dx

Divide (3x^2-4x+3) by (2x-1)

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