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`int_(0) ^(pi//2) cos^(2) theta d theta =`
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`int_(0)^(2pi) (sin 2 theta)/(a-b cos 2 theta )d theta = `
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Integral of (pi^2-x^2)^(1/2) on zero to pi using a trig substitution let x=pi*cos(theta).
int(0, pi/4) (1 + cos^2(theta))/cos^2(theta) d theta, Evaluate the integral.
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