結果 : integration of cosx limit 0 to pi/2
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Evaluate `int_0^(pi/2) x/(sinx+cosx)dx`

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Prove that integral of cos square x upon sinx plus cosx dx from 0 to pi by 2 equal 1/√2 log(√2 + 1)

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The value `int_0^(pi/2)(sinxcosx)/(cos^2x+3cosx+2)dx` is

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