Evaluate the Integral 1/(9x^2 -16) dx. Partial Fraction Decomposition. Integrate

`int (dx)/(sqrt(9x^(2)+16))`

微積分ヘルプ: ∫ 1/(9x^2-16) dx - 三角関数の置換による積分 - テクニック

Integration of 1/16+9x^2 dx

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微積分ヘルプ: 積分 ∫ 1/((x^2-1)^(3/2) ) dx - 三角関数の置換による積分

Integral of x^2/(x^2+1)

integral of 1/(x^2+1) but you didn't learn it this way in calculus 2

微積分ヘルプ: (16-9x^2 )^(3/2)/x^6 dx の積分 - 置換積分

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Integral of 1/(x^2-1) (partial fraction decomposition)