`int(sec^2x)/((secx+tanx)^(9/2))dx`

The integral `int (sec^2x)/(secx+tanx)^(9/2)dx` equals to (for some arbitrary constant `K`) (A) `-

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The integral ∫▒(〖sec〗^2 x)/〖(secx+tanx)〗^(9/2) dx equals:a)-1/〖(secx+tanx)〗^(11/2) {1/11-1/7 〖(sec

Integral sec^2 x/(sec x +tan x)^9/2 ,an IIT-JEE interesting problem, solution by Dig Your Mind

The integral `(sec^2x)/ (sec x+ tan x)^(9/2)` is equal to

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