How do I integrate log (cos x) from 0 to pi/2? Log sinx dx from 0 to pi by 2
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integration 0 to 'pi/2' ln(cosx)dx || integration 0 to 'pi/2' log(sinx)dx || 0 to pi/2 ln(cosx)dx
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Prove that: `int_(0)^(pi//2) log (sin x) dx =int_(0)^(pi//2) log (cos x) dx =(-pi)/(2) log 2`
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Differentiation and integration important formulas||integration formula