結果 : integration of sin 4t + 2t
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The Laplace transform of e^(-2t) sin⁡4t is (a) 4/(s^2+4s+25) (b) 4/(s^2+4s+20)

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Limit t →0 [1/((1-2t)(1+4t))]^(1/t). Solve WITHOUT using L' Hôpital's Rule. Solve by Taylor Series.

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