微積分ヘルプ: sin2y √(3+sin^2⁡y ) dy の積分 - 置換積分

integrate cos^2 (2y) × sin (2y) dy

integral of (cosy)³ (sin2y)³dy

Solution of : dy/dx + x sin2y = (x^3) (cos^2y)

微積分ヘルプ：ベルヌーイの微分方程式 - dy/dx+x sin2y=x^3 cos^2⁡y - テクニック

Solve dy/dx = 1/(xcosy +sin2y) with initial value y(1)=0

Solve: dy/dx + x sin 2y=x^3 cos^2 y || First order ODE || Differential equation

Bernoullies differential equation. equation reducing to linear form.dy/dx+x.sin2y=x^3.cos^2y.

Calculus Help: Linear Differential Equations - Integrating Factor - dy/dx= 1/(x cosy+sin2y) -

(dy)/(dx)=(sin2y)/(x+tany) | 12 | DIFFERENTIAL EQUATIONS OF THE FIRST ORDER AND FIRST DEGREE | ...

`int(dy)/(cosy+sin2y)=`

積分 ∫ (sin2y ln^3⁡ (1+sin^2 y))/(1+sin^2⁡ y )dy または ∫ (sin2x ln^3⁡ (1+sin^2⁡ x))/(1+sin^2⁡ x) dx

Math: find the dy/dx #calculus #differentiation #maths #education

Bernoulli's Equation | dy/dx + x sin2y = x³ cos²y@EAG

微積分ヘルプ: 分離可能な微分方程式 - cosx sin^2⁡y dx+sinx sin2y dy=0

EXACT EQUATIONS #11| (cos 2y-3x^2y^2) dx+(cos 2y-2x sin 2y-2x^3y) dy=0

微積分ヘルプ：分離可能な微分方程式 - sinx cosy dy+cosx sin2y dx=0 - テクニック

Q56 | If x sin⁡2y=y cos⁡2x, find dy/dx.

The solution of the differential equation `(dy)/(dx)=(siny+x)/(sin2y-xcosy)` is (a) `sin^(2) y=

Find dy/dx in the following:sin2y + cos xy = K.#onlinegurukulbyrohitranjan