|| Evaluate integral tan inverse of (3x-x^3)/(1-3x^2).dx ||in Telugu|| engineering mathematics 2||

Evaluate the following integrals: `inttan^(-1)((3x-x^(3))/(1-3x^(2)))dx`

#Evaluate integral tan inverse of (3x-x^3)/(1-3x^2).dx # short#M2

`tan^(-1)((3x-x^(3))/(1-3x^(2)))`

y=`tan^(-1)((3x-x^(3))/(1-3x^(2)))`Find dy/dx

Find dy/dx if y = tan^-1(3x-x³/1-3x²) | Differentiate of tan inverse 3x minus x cube by 1 minus 3x

Integrate : int tan^(-1) [(3x-x^(3))/(1-3x^(2))]dx [-(1)/(sqrt(3))lt x lt(1)/(sqrt(3))] | 12 | I...

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Differentiate `tan^(-1)((3x-x^3)/(1-3x^2)),if` `-1/sqrt(3)ltxlt1 /sqrt(3)`(2)`xgt1/sqrt(3)``( 3...

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