|| Evaluate integral tan inverse of (3x-x^3)/(1-3x^2).dx ||in Telugu|| engineering mathematics 2||

`tan^(-1)((3x-x^(3))/(1-3x^(2)))`

Evaluate the following integrals: `inttan^(-1)((3x-x^(3))/(1-3x^(2)))dx`

y=`tan^(-1)((3x-x^(3))/(1-3x^(2)))`Find dy/dx

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Integrate : int tan^(-1) [(3x-x^(3))/(1-3x^(2))]dx [-(1)/(sqrt(3))lt x lt(1)/(sqrt(3))] | 12 | I...

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Define: `tan^(-1)((3x-x^(3))/(1-3x^(2)))` in terms of `tan^(-1)x`

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