Integral of x/(x^2+4x+5) (substitution)

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Calculus Help: Integral dx/(x^2-4x-5) - Integration by partial fractions - Techniques

2. Integrate: (x) ∫ x dx/√(x² + 4x + 5) int xdx/sqrt(x²+4x+5) Antiderivative Calculus "MSI" NEB 12💥🌻

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`intsqrt(x^2-4x-5)dx=`

y = x^2 - 4x - 5, y = 0, between x = -1 and x = 4

Evaluate the Integral (x+4)/(x^2 +2x +5) dx.

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integrate (x-1)/(x^2 - 4x - 5) dx from x=0 to 4

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Evaluate definite integral x/(x^2 +4x +13) dx over [0, 1].

`int(dx)/(x^2+4x-5)=`

Integral of ∫dx / (x^2 + 4x + 5) by Trigonometric Substitution

`(x^(2) - 4x+5) (x^(3) - 2)`