How to write the inverse of the square root function
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If `x=7-4sqrt3` then find the value of `sqrtx+1/sqrtx`
Find the Inverse of the Linear Function f(x) = 4x + 7
"If `x=7+4sqrt(3)\ \ a n d\ x y=1`, then `1/(x^2)+1/(y^2)=`64 (b) 134 (c) 194 (d) `1/(49)`"
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integrate 5/sqrt(x-7) dx
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If x = 7+4 root 3 then find the value of x + 1/x
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if x=7 + 4√3 and xy=1 then 1/x^2 +1/y^2=
Derivative of f(x) = (2x - 7)/sqrt(x)
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