Q41 | Prove that 1 upon 1 + sin theta plus 1 upon 1 - sin theta = 2 sec square theta | 1/1+sin⁡θ + 1

sin square theta + cos square theta = 1 How to prove?

sintheta-costheta+1/sintheta+costheta-1=1/sec theta-tan theta

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1 upon secant squared theta minus cos squared theta + 1 upon cos squared theta minus

If 1 + sin square theta = 3 sin theta cos theta then prove that tan theta = 1 or 1/2

Q3 | Prove that 1 + tan square theta into 1 - sin theta into 1 + sin theta = 1 | 1+tan^2⁡θ 1-sin⁡θ 1

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prove that 1/cosec theta - cot theta - 1/sin theta = 1/sin theta - 1/cosec theta + cot theta.

Prove that (1)/(1+sin theta)+(1)/(1-sin theta)=2 sec^(2) theta | prove that 1/1+sina+1/1-sina=2sec2a

Sin シータ/1+Cos シータ + 1+Cos シータ / Sin シータ = 2 Cosec シータ |数学クラス 10 |身元

#Trigonometry all formulas

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Prove that (1)/(1+sin theta)+(1)/(1-sin theta)=2 sec^(2)theta | Prove that 1/1+sina+1/1-sina=2sec2a.

Prove that root 1+sin theta /1-sin theta=sec theta + tan theta

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Prove: (tanθ+secθ-1)/(tanθ-secθ+1)=(1+sinθ)/cosθ. Class-10 Trigonometry important problem