結果 : partial derivative of sqrt x 2 y 2
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Second order partial derivatives: f(x,y) = sqrt(x^2 + y^2)

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Find both first partial derivatives. z=2y^{2}\sqrt{x} | Plainmath

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Directional Derivative of g(x, y) = sqrt(x^2 + y^2) at (3, 4) in the direction of v = 8i - 15j

The Math Sorcerer
5,411 回視聴 - 7 年前

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ラーソン微積分 13.3 #28: g(x, y) = ln(sqrt(x^2 + y^2)) の一次偏微分

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y = sqrt(9 - x^2)の微分dyを求めよ

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Chain Rule | y=[ln(x + sqrt(x^2-1))]

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Find the derivative of y = ln (x * sqrt(x^2+10))

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[FOREIGN] - if y = [x+ \sqrt (1+x^2 )]^n then show that (1+x^2) d2y/dx2 + x dy/dx = n^2 y

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Implicit Differentiation sqrt(x)=sqrt(y), dy/dx=...

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Partial Differentiation of U= Log root X^2+y^2+z^2 , Prove that (X^2+y^2+z^2)(d^2u/Dx^+D^2u/Dy^2+...

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28,420 回視聴 - 3 年前
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u=tan—1[xy / √1+ x²+y² ]then prove that ∂̇²u/∂x∂y=1/(1+x²+y²)^3/2 . #partialdifferentiation#bsc1

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lim (x,y) approaches (2,2) of (x+y-4)/(sqrt(x+y)-2)

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