`2x^3-x^2 -22x-24=0`, two of the roots being in the ratio of 3:4
Solve the equation 2x ^ 3 - x ^ 2 - 22x - 24 = 0 two of the roots being in the ratio of 3: 4.
\( 2 x^{3}-x^{2}-22 x-24=0 \), two of the roots being in the ratio of \( 3: 4 \).
Factor 3x^2 + 22x + 24
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