If α,β are the roots of equation x²-2x+4=0 then positive integer n show that αⁿ+βⁿ = 2ⁿ⁺¹cos(nπ/3)

If α and β are the roots of equation x² – 2x + 4 = 0, then what is .......?(#SSCCGL Maths Questions)

The sum of the roots of the equation, x^2+|2x-3|-4=0, is

If α and β are the roots of equation x2 – 2x + 4 = 0, find the equation α^3/ β^2 and β^3/ α^2?

Solve by completing the square for x^2 + 2x - 4 = 0

Solve x²-2x-4=0 by using quadratic formula||Quadratic equations||Quadratic Formula

L-7, Q5 If α, β be the roots of x² -2x +4=0 T.P. αⁿ + βⁿ = 2^(n+1) cos nπ/3 |Trigonometry&Matrices |

Solve quadratic equation by factorisation

If ` alpha and beta` are the roots of the equation `x^(2) - 2x + 4 = 0` , then what is the

Solve by completing the square | Step by Step Technique

alpha and beta roots of quadratic equation | Finding new equation

Solving Quadratic Equations by Factoring│Algebra

Solving a quadratic by completing the square

α and β are roots of equation x^2−2x+4=0, then find equation whose roots are α^3/β^2 and β^3/α^2

Factorisation of Functions with Square Roots

If alpha,beta are roots ofx^2-2x+4=0 then positive integer n showalpha^n+beta^n=2^(n+1)cos (n pi/3)

If `alpha,beta` are the roots of `x^2-2x+4=0` , then `alpha^5+beta^5` is :

4#DeMoivresTheorem α、β が x² - 2x + 4 = 0 の根である場合、α^n + β^n = 2^(n+1)Cos(nπ/3) であることを示します。

If are the roots of the equation x2 -2x + 4 = 0 , then the value of α^6+β^6 is | Quadratic Equation

二次公式を使用して二次方程式を解く - 二次方程式