if p is the perpendicular distance from origin to line x/a+y/b=1 then show that (1/p^2)=1/a^2+1/b^2.

Deriving Intercept form of Straight Line x/a+y/b=1 | Kamaldheeriya

The line x/a - y/b= 1, where a and b are positive constants, meets the x-axis at P and the y-axis at

Show that by using Vector Method x/a + y/b = 1 is the equation of a straight line in Intercept Form

A Variable straight lines passes through the point of intersection of lines x/a + y/b =1 and ….

The area of triangle formed by the line x/a+y/b=1 with coordinate axes is...|| MCQ RD Class 10 ||

reduce x/a+y/b=1 to normal form.show x/a^2+y/b^2=1/p^2 here p is perpendicular distance from origin

If the line x/a+y/b=1 passes through the point of intersection of the lines x+y=3.....

Prove that the line x=ay+b , z=cy+d and x=a'y+b ,z=c'y+d are perpendicular if aa'+cc'+1=0

Show that the lines x/a+y/b=1, x/b+y/a=1 and y=x meet at a point.

Prove that the line `x/a + y/b =1 and x/b - y/a =1` are perpendicular to each other.

Condition for a line to be tangent to the circle|(x−a)^2+(y−b)^2=r^2 if 1/a^2 +1/b^2 =1/r^2 | SD sir

The angle between the lines `x/a+y/b=1` and `x/a-y/b=1` will be:

NECO 2020 Question 30 | Equation of a straight line

The straight line `x/a+y/b=1` cuts the axes in A and B and a line perpendicular to AB cuts the...

If the line x/a +y/b =1 passes through the point of intersection of the lines x+y=3.....find a and b

Equation of Straight line(Double Intercept)form: x/a+y/b=1 @katari12345 #shorts #shortvideo #viral

If the line `(x/a)+(y/b)=1` moves in such a way that `(1/(a^2))+(1/(b^2))=(1/(c^2))` , where `c...

A variable line, drawn through the point of intersection of the straight lines x/a + y/b =1 & x/b +

P(a,b) is the mid-point of a line segment between axes. show that equation of the line is x/a+y/b=2