If tanθ=1/2 then evaluate { (cosθ/sinθ) + (sinθ/1+cosθ) }
`(sintheta + sin2theta)/(1+costheta+cos2theta)=tantheta`
`(1+sintheta-costheta)/(1+sintheta+costheta)=tantheta/2`
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Prove that cot theta - tan theta = 2 cos^2 theta -1/sin theta cos theta
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(sin θ + sin 2θ)/(1 + cos θ + cos 2θ) = tan θ
सिद्ध कीजिए कि (1-sin theta)/(1+sin theta)=(sec theta-tan theta)^(2)prove that 1minus sin theta upon
Prove that: `(1+sintheta-costheta)/(1+sintheta+costheta)=tantheta/2`
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sintheta-costheta+1/sintheta+costheta-1=1/sec theta-tan theta
If 1 + sin square theta = 3 sin theta cos theta then prove that tan theta = 1 or 1/2
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