結果 : sin x equals 1/3
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Solve equation sqrt(3) sin x + cos x =1. Give general solution.

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Evaluate definite integral (sin^3 x)/(1+ cos x) dx over [0, pi/2] using method of substitution

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Solve for all values of x when 2 sin x +1 =0 over [0, 360]

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'3sin^-1x=sin^-1(3x-4x^3)' x in [-1/2,1/2] |Prove that:3sin^(-1)x=sin^(-1)(3x-4x^3),x in [-1/2,1/2]

concepts & Methods
8,302 回視聴 - 3 年前
26:17

Expand f(x)=x sin⁡〖x 〗 as fourier series in (-π,π). Deduce that 1/1.3-1/3.5+1/5.7-1/7.9……..=(π-2)/4

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Solving Trigonometric Equations: sin x = 1/2

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Integration :- limit -1 to 3/2 mod xsinπx

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Find Fourier series for f(x)= xsinx for x in interval [-π,π]. Hence find 1/1.3-1/3.5+1/5.7= (π-2)/4

RK Eduworld (Classic)
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三角関数、cos(3x)/cos(x)=1/3 の場合、sin(3x)/sin(x)=?

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Integration 22 : Integration of 1/ (3+ 2 sin x + cos x) || JBR Online classes

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sin(x) = x – (x^3)/3! を評価する C プログラム+(x^5)/5! + (x^7)/7! + ..

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25,510,957 回視聴 - 1 年前
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If cos x + cos y `=(1)/(3) and sin x + sin y=(1)/(4)` prove that tan `((x+y)/(2))=(3)/(4)`

Doubtnut
3,376 回視聴 - 4 年前
20:21

Find Fourier series of f(x)=0, in (-pi ,0), sin x,in(0,pi) hence find 1 by 1.3+1 by 3.5+1 by 5.7+...

Simha's Classes
11,451 回視聴 - 1 年前

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3:46

Prove that: `3sin^(-1)x=sin^(-1)(3x-4x^3), x in [-1/2,1/2]`...

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6,918 回視聴 - 5 年前
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@btechmathshub7050Fourier series f(x)=xsinx

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22,731 回視聴 - 3 年前
5:08

If cos ` x=- (1)/(3) ` and x lies in Quadrant III find the values of `(i) " sin " .(x)/(

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8,701 回視聴 - 4 年前