Trigonometric equations Solve 〖2sin〗^2⁡(x)+sin(x)-1=0 Where 0≤x≤360

三角方程式を因数分解で解く: 2sin^2(x)-sin(x)-1=0 (ラジアン)

2sin^2(x) + 3sin(x) + 1 = 0 を解く

2*sin(x) - 1 = 0 を [0, 2pi) で解く

線形三角方程式を次の形式で解きます: 2sin(x)+1=0

Solve the Trig equation 2 sin^2 x - sin x - 1 = 0 on the interval [0, 2pi)

2sin^2(x) - 1 = 0 Solve for interval 0 less theta less 2pi

Solve for all values of x when 2 sin x +1 =0 over [0, 360]

2sin^2x+sinx-1=0を解く

Solve the equation 2 sin^2 x + 3 sin x + 1 = 0

Solve the equation. 2sin^2x-sinx-1=0

Solve the Trig equation 2 sin^2 x -1 = 0 on the interval [0, 2pi)

How to solve 2(sinx)^2+sinx-1=0 on [0,2pi)

Verify each x-value for 2sin^2(x) - sinx - 1 = 0 a) x=pi/2 b) x=7pi/6

Solve a Trigonometric Equation: 2sin^2(x)=1 over the interval [0,2pi)

Solving Trigonometric Equations, 2sin^2x+sinx-1=0, How to Solve Trigonometric Equations

Solving Trigonometric Equations 2sin^2x-sinx-1=0, How to Solve Trigonometric Equations

Solve the Trig equation 2 sin x +1 = 0 on the interval [0, 2pi)

Solve: 2sin^2 x – sinx – 1 is bigger than 0

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