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z^4=1-√3iを解く
1+ 1/2+ 1/4+ 1/8+ 1/16+ ........=? Can you solve This;
一次方程式を解く: 1/4x+1/2=2(4/5x+3)
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z^4=1を解く
問題 4 一次方程式 (y-1)/3 - (y-2)/4 = 1 を解きます。
"Solve `4 2/3+3 1/2-1 2/3=?``2 1/5`(b) `2 5/3`(c) `1 3/4`(d) `1 1/2`(e) `6 1/2`"
Solve the question: (-4)+(-1)+2+5+...+x = 437 || RD Question Class 10 || Arithmetic Progression ||
"Solve `7 1/2-[2 1/4+{1 1/4-1/2(1 1/2-1/3-1/6)}]=?``2/9`(b) `4 1/2`(c) `9 1/2`(d) `1(77)/(228)`"
8 Solve the equation – 4 + –1 + 2 + … + x = 437
Solve the equation -4+(-1)+2+…+x=437
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