Solve a Trig Equation Linear in Form: 2sin(x)+1=0
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三角方程式を因数分解で解く: 2sin^2(x)-sin(x)-1=0 (ラジアン)
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2sin^2(x) - 1 = 0 Solve for interval 0 less theta less 2pi
Solve the Trig equation 2 sin^2 x -1 = 0 on the interval [0, 2pi)
2sin(x) + 1 = 0 Solve for interval 0 less theta less 2pi
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