sum of n terms of series 1 2 3 4 7 8（関連順）

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Find the sum to n terms 1/2 + 3/4 + 7/8 + 15/16 + ...

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"Sum of the first `n` terms of the series `1/2+3/4+7/8+(15)/(16)+` is equal to (1988, 2M) `2^n-n-1

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The sum to n terms of the series` 1/2+3/4+7/8+15/16+..... is given by`

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The sum of the first n terms of the series 1/2+3/4+7/8+15/16+……… is (1) 2^n-n-1 (2) 1-2^-n (3) n+...

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The sum of the first n terms of the series 1/2+3/4+7/8+15/16+… is (a) 2^n-n-1 (b) 1-2^-n (c) n+2^...

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Sum of the first n terms of the series 1/2+3/4+7/8+15/16+⋯ is equal to

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結果 : sum of n terms of series 1 2 3 4 7 8