how to solve the trig equation tan(θ)=-sqrt(3), θ in [0, 360), precalculus tutorial
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6 The value of tan 1° tan2° tan 3° … tan 89° is
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The value of `tan1^@tan2^@tan3^@...tan89^@` is
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exact value for tan(15), using difference formula for tangent
The value of (tan 1^∘tan 2^∘tan 3^∘…tan 89^∘) is (A) 0 (B) 1 (C) 2 (D) 1/2