Let `cos(2 tan^(-1) x)=1/2` then the value of x is

Inverse trigonometric function || the value of cos[2tan^-1(x)] I| @goymath

Derivatives of inverse trigonometric functions sin-1(2x), cos-1 (x^2), tan-1 (x/2) sec-1 (1+x^2)

Simplify the expression cos(2 tan^(-1) x). Inverse Trig Functions

f(x) = cos (2 tan^(-1) sin(cot^(-1) sqrt((1-x)/(x)))), 0 lt x lt 1 とします。したがって、次のようになります。| 12 | 解決...

Inverse trig functions derivatives

cos(2tan^-1(x)) | cos(2arctan x)

次の方程式を解きます: `sin[2cos^(-1)\"{\"cot\"(\"2tan^(-1)x\"}]\"=0`

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