結果 : value of sin 2 pi by 3 in fraction
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Sin (2π/3) =?

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'sin^2(pi/6)+cos^2(pi/3)- tan^2(pi/4)=-1/2'

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Prove that: sin ^2π/6+cos ^2π/3-tan ^2π/4=-1/2 LHS = sin ^2π/6+cos ^2π/3-tan ^2π/4 = (1/2)^2+(1...

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