結果 : verify x 3 y 3 z 3 3xyz
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因数分解(x^3+y^3+z^3-3xyz)

voice (学べ!高校数学!)
3,470 回視聴 - 5 年前
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Prove that x³+y³+z³-3xyz=(x+y+z) (x²+y²+z²-xy-yz-zx) Algebraic identity derivation | Bharat Kumar

Indian Bharat
29,183 回視聴 - 4 年前

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cbse class9||Ex-2.5||Sum 12||NCERT Maths||Chapter2||Polynomials||verify x3+y3+z3-3xyz formula||Tamil

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270 回視聴 - 4 年前
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Ex 2.5 Q12. Verify that x^3+y^+z^3+3xyz

Kwatra Tuition Center
309 回視聴 - 4 年前
0:21

x3 + y3 + z3 – 3xyz = (x + y + z)(x2 + y2 + z2 – xy – yz − xz)

গণিত শিক্ষণ WITH সুজয় স্যার
394 回視聴 - 3 年前

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proof of x^3 + y^3 + z^3 - 3xyz = (x + y + z)(x^2 + y^2 + z^2 - xy - yz - zx)

Dr. Mohan (mpduty)
1,204 回視聴 - 5 年前
6:26

Verify that x^3+y^3 + z^3- 3xyz =1/2(x+y+z)[(x-y)^2+(y-z)^2+(z-x)^2]

BRAINO SOLUTIONS
394 回視聴 - 2 年前
4:48

9th.. x³+y³+z³-3xyz=1/2(x+y+z)[(x-y)²+(y-z)²+(z-x)²]

dev classes Dehradun
37,347 回視聴 - 3 年前
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Class 9, Maths, Ch-2, Polynomials and factorisation, Ex 2.5, Q. No 12

MRMSVarni DC
209 回視聴 - 5 年前
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FACTORISATION OF x³+y³+z³-3xyz = (x+y+z) (x²+y²+z²-xy-yz-zx) | In Hindi

Complex Point
21,287 回視聴 - 4 年前
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Verify Std 9 Maths Ex 2 5 Q 12 and 13

Sunilkumar Jadhav
3,728 回視聴 - 5 年前
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Verify x3+y3+z3–3xyz = (1/2)(x+y+z)[(x–y)2+(y–z)2+(z–x)2] | Class - 9th Ex- 2.5 Q12 (POLYNOMIALS)

Shruti Academy
19,666 回視聴 - 3 年前
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Verify that x3+y3+z3-3xyz=1/2(x+y+z) (x-y)2+(y-z)2+(z-x)2 | Class 9 Maths Ch 2 Ex 2.5 Q12

Garg Tutorials
17,318 回視聴 - 2 年前
4:35

Class 9 Polynomials Ex 2.4 Q12/Verify x3+y3+z3-3xyz=1/2(x+y+z) (x-y)2+(y-z)2+(z-x)2#maths #ncert

ROSEYMATHSCLASS
1,164 回視聴 - 1 年前
7:51

Verify that: x^3+y^3+z^3-3xyz=1/2 (x+y+z)[(x-y)^2+(y-z)^2+(z-x)^2] || Polynomials |Class-9th |NCERT|

MATHEMATICS ADVISOR
2,322 回視聴 - 3 年前
3:34

x3+y3+z3-3xyz=1/2(x+y+z) [(x-y)2+(y-z)2+(z-x)2] | であることを確認します。 Ex 2.5 クラス 9 [Q12]

R&H Academy
6,402 回視聴 - 4 年前
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Verify That x3+y3+z3-3xyz=1/2(x+y+z) (x-y)2+(y-z)2+(z-x)2 | Class 9th Ex 2.5 Question 12

AK MtCourse
72,320 回視聴 - 5 年前
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Verify that x³+y³+z³ = 1/2 (x+y+z) [ (x-y)²+(y-z)²+(z-x)² ] Polynomials Class9th #maths #ncertmaths

Calculus
2,488 回視聴 - 2 年前
10:33

verify that x3+y3+z3-3xyz=1/2(x+y+z) (x-y)2+(y-z)2+(z-x)2

Foundation Physics - Reza Ahmed
1,799 回視聴 - 5 年前
4:35

`x+y+z=9` かつ `xy+yz+zx=23` の場合、 `(x^3+y^3+z^3-3xyz)=? ` の値は

Doubtnut
13,891 回視聴 - 5 年前