'cot^2(pi/6)+cosec(5pi/6)+3tan^2(pi/6)=6'|| `cot^(2)pi/6+\"cosec\"(5pi)/(6) + 3tan^(2)pi/6=6`
3. cot^2 pi/6 + cosec^2 5 pi/6 + tan^2 pi/6 = 6
`cot^(2)pi/6+\"cosec\"(5pi)/(6) + 3tan^(2)pi/6=6`
Exact Value of cot(-pi/6) - Unit Circle Survival Guide
Prove cot^2(pi/6) + cosec(5pi/6) + 3 tan^2(pi /6) =6
cot^2 π/6 + cosec 5π/6 + 3tan^2 π/6 = 6
`cot^2` `pi/6` `+cose c` `(5pi)/6` `+3tan^2` `pi/6=6`...
Compute cot(pi/6)
Find the value of cot^2 pi6 + cosec 5pi6 + 3tan^2 pi6 = 6
cot(-pi/6)
The value of `(tan^2)pi/3+4(cos^2)pi/4+3(sec^2)pi/6+(cot^2)pi/2` is
What is the value of (𝟒/𝟑)𝐜𝐨𝐭^𝟐 (𝛑/𝟔)+𝟑 𝐜𝐨𝐬^𝟐 (𝟏𝟓𝟎°)−𝟒 𝐜𝐨𝐬𝐞𝐜^𝟐 𝟒𝟓
Prove that: \[ \cot ^{2} \frac{\pi}{6}+\operatorname{cosec} \frac{5 \pi}{6}+3 \tan ^{2} \frac{\p...
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3. 〖cot〗^2 π/6+cosec 5π/6+3〖tan〗^2 π/6=6
CLASS 11 CH 3 TRIGONOMETRIC FUNCTIONS EXERCISE 3.3 QUESTION 3 cot2 Π/6 + cosec 5Π/6 + 3tan2 Π/6 = 6
NCERT +1 maths chapter 3 trigonometry cos(3π/2 + x)cos(2π+x)[cot(3π/2-x) + cot(2π+x)]= 1
Evaluate lim(x→π/6) cot^2(x)-3/cosecx-2 || limit X tend to pi by 6 cot^2 x - 3 / cosec x - 2
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