結果 : what is n ab in sets
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A と B が、n(A)=n(B) かつ n(B-A)=3x かつ n(A nn B)=x において n(A-B)=14+x となる 2 つの集合であるとします。すると...

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If \( n(A)=115, n(B)=326, n(A-B)=47 \), then \( n A \cup B \) is equal to (A) 373 (B) 165 (C) 37...

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n(A∪B)=?, n(A-B)=?, n(AΔB)=?, n(A∪B∪C)=?, n(A^C∪B^C)=?, n(A^C∩B^C)=?, n(A∩B∩C^C)=?, n(A∩B^C∩C^C)=?

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