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If `f(x)=cosx.cos2x.cos4x.cos8x.cos16x` , then `f'(pi/4)` is :
The derivative of the function cot^-1{(cos 2 x)^1/2} at x =π/6 is
If `f(x) = cosx cos2x cos4x cos8x cos16x` then `f'(pi/4)` equals
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if tan²y=(1+ cos2x) /(1-cos2x), then find dy/dx