Implicit Differentiation: e^(2xy)+y^4+x^3=1
例: 暗黙微分と積分則を使って dy/dx を求める - e^(2xy)=y^n
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First Order Partial Derivatives of f(x, y) = e^(xy)
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Implicit Derivative: 𝑥^2+2𝑥𝑦+2𝑦^2=5
Derivative of x^2 + 2xy + y^2 = 0 (Implicit differentiation)
微積分ヘルプ: 方程式 x^2-2xy+y^2-6x+2y=0 の微分を求める - テクニック
Partial Derivatives - Multivariable Calculus
Solve the differential equation y(2xy+e^x)dx = e^x dy
関数の偏微分を求める方法
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Every derivative of the form e^(ax), derivatives of exponential functions
dy/dx+2xy=e^(-x^2) #LinearEquation L629 @MathsPulseChinnaiahKalpana
Find the derivative of 2xy + y^2 = x + y
Differential Equations Practice #13: dy/dx = e^(2x - y)
csc(x) * e^(2x)の微分積と連鎖律の例